Problem Understanding
Given an array of intervals where intervals[i] = [starti, endi], merge all overlapping intervals, and return an array of the non-overlapping intervals that cover all the intervals in the input.
Example:
- Input:
[[1,3],[2,6],[8,10],[15,18]] - Output:
[[1,6],[8,10],[15,18]] - Explanation: Since intervals
[1,3]and[2,6]overlap, merge them into[1,6].
Algorithm Strategy
- Sort the Intervals: First, sort the intervals based on their start times. This brings potentially overlapping intervals next to each other.
- Iterate and Merge: Create a
mergedlist and add the first interval. - Compare: For each subsequent interval, check if it overlaps with the last interval in the
mergedlist (i.e.,current.start <= last.end). - Update: If they overlap, update the last interval's end time to
max(last.end, current.end). If they don't, simply append the current interval to themergedlist.
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